Are 5/27 and 8/9 in the Cantor Set?

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SUMMARY

The discussion confirms that 8/9 is included in the Cantor set C_2, as it corresponds to the base 3 representation (0.22)_3, which is an endpoint of one of the closed intervals. In contrast, 5/27 is not part of the Cantor set C_3 due to its base 3 representation (0.012)_3 containing a '1', indicating its exclusion from the set. The correct intervals for C_3 are identified as [0,1/27] ∪ [2/27,3/27] ∪ [6/27,7/27] ∪ [8/27,9/27] ∪ ..., confirming the removal of 5/27 from the set.

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Homework Statement



I am trying to find if 5/27 and 8/9 are in the Cantor set.

Homework Equations



C_2=[0,1/9]\cup[2/9,3/9]\cup...\cup[8/9,1]

C_3=[0,1/27]\cup[2/27,3/27]\cup[4/27,5/27]\cup...\cup[26/27,1]

The Attempt at a Solution



I have: 8/9=(0.22)_3
and it is an endpoint in one of the closed sets of C2, so it is in the Cantor set.

I also have: 5/27=(0.012)_3
It is an endpoint in C3, but doesn't the 1 in the base 3 expansion mean that it isn't part of the Cantor set?
 
Last edited:
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Your C_3 is wrong. The interval \left[\frac{4}{27},\frac{5}{27}\right] is not part of the third stage of the Cantor set. Can you think about what would be the correct interval?
 
Oh yes, how stupid of me.

It's:

[0,1/27]\cup[2/27,3/27]\cup[6/27,7/27]\cup[8/27,9/27]\cup...

So 5/27 has been removed. Thanks.
 

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