Are gravitational "fields" additive? By this I mean, if you are placed directly between two solid massful objects, that are somehow held still for this example(maybe binary system revolving around the center of mass).: You would not move because of an unstable equillibrium, true. But does your equations for fields at that point ADD, or equate to zero? I guess what I'm asking is, I know there are some effects that are affected by gravitation fields, so by being in the presences of two equally stong fields, is that effect doubled? or cancelled out? I would assume doubled. Seems that just because a sum of the force vectors due to potentials zero out in 3D, from that observation point, doesnt mean that there isnt still a displacement of curvature when compared to a flat plane. Though I understand this curvature would be relative to the observer at the point, or distant outside the group. Or WOULD it be so locally flat, at that exact point, that it WOULD be zero? I'm imagining a maxima of some sort, where you could either say zoomed in it approaces a flat plane for its derivative, or looking a little larger you see that there is curvature.