I Are spherical transverse waves exact solutions to Maxwell's equations?

AI Thread Summary
The discussion centers on the claim from a NASA paper that spherical transverse waves are solutions to Maxwell's equations in the limit as kr approaches infinity. It highlights the divergence and curl of the electric field, noting that certain terms do not vanish unless r approaches infinity. The conversation questions whether this implies that spherical waves are not exact solutions in a vacuum, despite the paper considering a homogeneous medium. It concludes that spherical waves are indeed approximate solutions, relying on specific assumptions such as r' being much smaller than r and kr being much greater than one. Overall, the findings suggest that while spherical waves can be treated as solutions under certain conditions, they require careful consideration of their limitations.
Delta2
Homework Helper
Insights Author
Messages
6,002
Reaction score
2,628
TL;DR Summary
Spherical waves as solutions to Maxwell's equations in vacuum.
In this paper in NASA

https://www.giss.nasa.gov/staff/mmishchenko/publications/2004_kluwer_mishchenko.pdf

it claims (at page 38) that the defined spherical waves (12.4,12.5) are solutions of Maxwell's equations in the limit ##kr\to\infty##. I tried to work out the divergence and curl of ##\vec{E(r,t)}## and find out that for example the divergence of E contains a term $$\frac{e^{ikr}}{r}\nabla\cdot\vec{E_1(\hat r)}$$, which doesn't seem to vanish (given the extra conditions (12.6-12.9) unless of course we take the limit ##r\to\infty##.

Is it that what it means at first place when it says that these waves are solutions in the limit ##kr\to\infty##? Does this means that spherical waves are not exact solutions to Maxwell's equations in vacuum? (the paper considers the general case of a homogeneous medium present but vacuum is a special case of a homogeneous medium isn't it?)

P.S ##\vec{E_1(\hat r)}## cannot be a constant vector as that is implied by 12.6, that is it is always perpendicular to ##\hat r##.
P.S2 I find no easy way to prove that ##\nabla\cdot\vec{E_1}=0## from the 12.6-12.9 conditions

P.S3 I think I got it now. The authors of the paper say that ##\vec{E_1}## (and ##\vec{H_1}##) must not depend on r. If so then their divergence and curl have ##\frac{1}{r}## dependence which together with the other ##\frac{1}{r}## from the term ##\frac{e^{ikr}}{r}## make a term ##\frac{1}{r^2 }##which can safely be neglected for ##r\to\infty##.
 
Last edited:
Physics news on Phys.org
Spherical waves are approximate solutions to Maxwell's equations. You have to make approximations based on the assumptions $r'<<r$ and kr>>1.
 
  • Like
Likes vanhees71 and Delta2
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...
Back
Top