Are vectors independent of reference frames?

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SUMMARY

This discussion clarifies the relationship between vectors and reference frames, emphasizing that while vectors themselves are independent of frames, their components are not. The equation connecting vectors in different frames is given as X = R + Q.V', where Q is the rotation tensor. The participants agree that in a physics context, vectors must adhere to tensor transformation rules, while in pure mathematics, a "vector" may not necessarily transform as expected. This distinction is crucial for understanding vector behavior across different coordinate systems.

PREREQUISITES
  • Understanding of vector notation and terminology
  • Familiarity with rotation tensors in physics
  • Basic knowledge of coordinate transformations
  • Concept of independence of vectors in physics versus mathematics
NEXT STEPS
  • Study the properties of rotation tensors in detail
  • Learn about tensor transformations in different reference frames
  • Explore the mathematical definitions of vectors versus physical vectors
  • Investigate applications of vectors in physics, particularly in mechanics
USEFUL FOR

This discussion is beneficial for physicists, mathematicians, and students studying mechanics or vector calculus, particularly those interested in the implications of reference frames on vector components.

TonyEsposito
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Ok, this is the notation I am going to use in this thread: uppercase means vectors, while "[V]c" means coordinates of vector V in frame c.
I'm reading from a book: i have a reference frame "a" and a reference frame "b" rotated with respect to "a", the vector connecting the frames origin is R.
We are tracking a particle having radius vector X in frame a and X' in frame b, the book says that the relation connecting the two vector is:

X=R+Q.V'
where Q is the rotation tensor of the two frames...but arent vectors indipendent of frames? should not the relation be simply:

X=R+V'

and only when expressed in a coordinates Q comes into play?

[X]a=[R]a+Q.[V']b
[X]b=[R]b+Q^-1.[V']a
 
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TonyEsposito said:
but arent vectors indipendent of frames?
They are... But their components are not. If you rotate or stretch or shrink or deform your coordinate frame the components change which what those tensors are used for.
 
I agree, as long as the term "vector" is interpreted in the physics/tensor context. In a pure mathematical context, it is possible to call something a "vector" where it does not transform as a tensor would. (A mathematician might define something like (1,0) as a unit "vector" even though it does not transform at all.)
 

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