- #1
etotheipi
This is a semantic question, without any implications really, but I wondered if someone could check if I understand this correctly? The angular velocity ##\vec{\Omega}## of a frame ##\mathcal{F}## with respect to another frame ##\mathcal{F}'## is defined such that, for any vector ##\vec{a}##,$$\left(\frac{d\vec{a}}{dt} \right)_{\mathcal{F}'} = \left(\frac{d\vec{a}}{dt} \right)_{\mathcal{F}} + \vec{\Omega} \times \vec{a}$$The property of addition of angular velocities between frames follows quite naturally,$$\left(\frac{d\vec{a}}{dt} \right)_{\mathcal{F}''} = \left [\left(\frac{d\vec{a}}{dt} \right)_{\mathcal{F}} + \vec{\Omega}_1 \times \vec{a} \right] + \vec{\Omega}_2 \times \vec{a} = \left(\frac{d\vec{a}}{dt} \right)_{\mathcal{F}} + (\vec{\Omega}_1 + \vec{\Omega}_2) \times \vec{a}$$Sometimes, we might say a particle or a rigid body has an angular velocity of ##\vec{\omega}## with respect to some coordinate system. Whilst this seems passable if there are only two frames involved, it doesn't seem like a good terminology otherwise. For instance, whilst it makes perfect sense to say that the angular velocity of frame ##\mathcal{F}## w.r.t. ##\mathcal{F}''## is ## (\vec{\Omega}_1 + \vec{\Omega}_2)##, it doesn't seem to make sense to say a particle has an angular velocity of ## (\vec{\Omega}_1 + \vec{\Omega}_2)## w.r.t. ##\mathcal{F}##. Instead, to get anything meaningful for the particle, you need to explicitly perform the change of coordinates ##\vec{r}'' = \vec{R} + \vec{r}## and differentiate (making use of the second equation), e.g. casting it in terms of ##\vec{v}'' = \vec{V} + (\vec{\Omega}_1 + \vec{\Omega}_2) \times \vec{r}##.
I wondered if you guys would agree that it's better to talk about the angular velocity of the frame in which the particle is at rest (or the body fixed frame of a rigid body), rather than the angular velocity of the particle itself? Thanks
I wondered if you guys would agree that it's better to talk about the angular velocity of the frame in which the particle is at rest (or the body fixed frame of a rigid body), rather than the angular velocity of the particle itself? Thanks