Are you positive about part 2 in Helicopter Kinetics and Motion

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SUMMARY

The discussion focuses on solving a physics problem involving a helicopter flying at a constant speed of 6.8 m/s and altitude of 9.9 m, from which a package is ejected horizontally at 11.0 m/s relative to the helicopter. The initial velocity of the package relative to the ground is calculated using vector subtraction, yielding a result of 4.2 m/s. The horizontal distance traveled by the package upon impact with the ground and the angle of its velocity vector before impact are also determined using kinematic equations. Accurate application of these equations is crucial for solving the problem correctly.

PREREQUISITES
  • Understanding of kinematic equations, specifically Vy2=Voy2-2*g*(y-yo) and Vy = Voy+g*t
  • Knowledge of vector subtraction in physics
  • Familiarity with projectile motion concepts
  • Basic algebra for solving equations
NEXT STEPS
  • Study vector addition and subtraction in physics contexts
  • Learn about projectile motion and its equations
  • Explore the application of kinematic equations in real-world scenarios
  • Practice solving problems involving relative motion and impact angles
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Students studying physics, particularly those focusing on kinematics and projectile motion, as well as educators looking for problem-solving strategies in mechanics.

DarPodo
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Homework Statement



A helicopter is flying in a straight line over a level field at a constant speed of 6.8 m/s and at a constant altitude of 9.9 m. A package is ejected horizontally from the helicopter with an initial velocity of 11.0 m/s relative to the helicopter, and in a direction opposite the helicopter's motion.

1)Find the initial velocity of the package relative to the ground.

2)What is the horizontal distance between the helicopter and the package at the instant the package strikes the ground?

3)What angle does the velocity vector of the package make with the ground at the instant before impact, as seen from the ground?

Homework Equations



Vy2=Voy2-2*g*(y-yo)

Vy = Voy+g*t

The Attempt at a Solution



1) To find the initial velocity of the package to the ground I thought it was just a simple vector subtraction of 11m/s - 6.8m/s ... my online homework CAPA says that the result is not correct, but I don't know another method.

2) This problem requires me having the correct solution for part 1. I would use the time taken for the package to hit the ground (using t = v/g) and then do:
(t * the velocity from part 1) + (t*6.8) = distance traveled by the package when it hits the ground. I can't test that out unless I have part 1 correct.

3) Again, I would need part 1 correct, but I'm thinking it's just inverse tan to solve.
 
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DarPodo said:

Homework Statement



A helicopter is flying in a straight line over a level field at a constant speed of 6.8 m/s and at a constant altitude of 9.9 m. A package is ejected horizontally from the helicopter with an initial velocity of 11.0 m/s relative to the helicopter, and in a direction opposite the helicopter's motion.

1)Find the initial velocity of the package relative to the ground.

2)What is the horizontal distance between the helicopter and the package at the instant the package strikes the ground?

3)What angle does the velocity vector of the package make with the ground at the instant before impact, as seen from the ground?

Homework Equations



Vy2=Voy2-2*g*(y-yo)

Vy = Voy+g*t



The Attempt at a Solution



1) To find the initial velocity of the package to the ground I thought it was just a simple vector subtraction of 11m/s - 6.8m/s ... my online homework CAPA says that the result is not correct, but I don't know another method.

2) This problem requires me having the correct solution for part 1. I would use the time taken for the package to hit the ground (using t = v/g) and then do:
(t * the velocity from part 1) + (t*6.8) = distance traveled by the package when it hits the ground. I can't test that out unless I have part 1 correct.

3) Again, I would need part 1 correct, but I'm thinking it's just inverse tan to solve.

Maybe the answer you are getting for part 1 is not positive...
 
DarPodo said:
Maybe the answer you are getting for part 1 is not positive...
Talking to yourself, hey? :wink:I do it a lot myself. :smile: Yes, you are correct about part 1 not being positive, but are you positive:rolleyes: about your method in part 2? You have 2 relevant equations you did not list.
 

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