Area between 2 curves, just need someone to check my work.

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SUMMARY

The discussion focuses on finding the area between the curves defined by the equations x = y² and 2y + x = 3. The user correctly identifies the points of intersection at y = -3 and y = 1. They set up the integral for the area as ∫ from -3 to 1 of (3 - 2y - y²) dy, and upon integrating, they arrive at the final area of 32/3. The calculations and methodology presented are accurate and confirm the user's solution.

PREREQUISITES
  • Understanding of integral calculus
  • Knowledge of curve equations and intersections
  • Familiarity with setting up definite integrals
  • Ability to perform polynomial integration
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  • Learn about the applications of definite integrals in real-world problems
  • Explore advanced techniques in polynomial integration
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Kuma
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Homework Statement


Alright so the problem:

Find the reigon in the xy plane that is bounded by the curves:

x = y^2
and
2y + x = 3


quickly solving for the y coordinates of intersection, i get
y = -3 and 1

so using horizontal components i got:

[tex]\int^{1}_{-3}[/tex] 3-2y - y^2

and then integrating and quickly solving i get 32/3 as a final answer
do the steps seem alright or have i made a mistake somewhere?

Many thanks :)
 
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