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Alright so the problem:

Find the reigon in the xy plane that is bounded by the curves:

x = y^2

and

2y + x = 3

quickly solving for the y coordinates of intersection, i get

y = -3 and 1

so using horizontal components i got:

[tex]\int^{1}_{-3}[/tex] 3-2y - y^2

and then integrating and quickly solving i get 32/3 as a final answer

do the steps seem alright or have i made a mistake somewhere?

Many thanks :)

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# Homework Help: Area between 2 curves, just need someone to check my work.

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