Consider the region enclosed by the curves x=2-y^2 and y=-x
Write a single integral that can be used to evaluate the area of the region. Find this area. Your answer should be a fraction reduced to its lowest terms.
The Attempt at a Solution
First, I graphed them and found the intersection points. The graphs intersect at the points (-2,2) and (1,-1). To write the integral, I decided to integrate with respect to y, I have:
Integral from y=2 to y=-1 of (-y)-(2-y^2)dy
Solving this, I got that the area should be 1.5, however I was told the answer is 4.5. Any ideas where I went wrong?