Area Calculation using Integrals: Finding the Minima of y=f(x)

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SUMMARY

The discussion centers on calculating the area bounded by the curve y = f(x) = x4 - 2x3 + x2 + 3, the x-axis, and the ordinates corresponding to the minima of the function. Critical points were identified at x = 0, 1, and 1/2, with minima occurring at x = 0 and x = 1. The area calculation from x = 0 to x = 1 yields an area of 91/30, despite initial confusion regarding the terminology of "ordinates." The discussion clarifies that "ordinates" refers to the vertical line at the critical points.

PREREQUISITES
  • Understanding of calculus concepts, specifically integrals
  • Familiarity with critical points and minima in functions
  • Knowledge of terminology related to coordinates, specifically "abscissa" and "ordinate"
  • Ability to perform definite integrals
NEXT STEPS
  • Study the process of finding critical points in polynomial functions
  • Learn how to perform definite integrals for area calculations
  • Explore the historical context and usage of mathematical terminology such as "ordinate" and "abscissa"
  • Practice solving similar area calculation problems using different functions
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Students studying calculus, mathematics educators, and anyone interested in understanding area calculations using integrals and critical points in polynomial functions.

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Homework Statement


The area bounded by the curve y = f(x) = x4 -2x3 + x2 + 3, the x-axis and the ordinates corresponding to the minimum of the function f(x) is?


The Attempt at a Solution



I found out the critical points as x= 0,1,1/2
Out of these, the minima occurs at 0 and 1

Since the question asks ordinates corresponding to the minimum, we get y = 0 for both x=0 and 1. Integrating from 0 to 0 is 0 offcourse. But the answer given is 91/30 which is obtained with limits 0 and 1 (which are abcissae). Is the question wording wrong?
 
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Hi Abdul! :smile:

hmm … yes of course, for a point (x0,y0), x0 is the abscissa, and y0 is the ordinate :confused:

I think the question is using the word "ordinate" to mean the line to (x0,y0) which is parallel to the y-axis or ordinate-axis, ie the line x = x0.

It's very confusing. And I thought everyone stopped using "ordinate" and "abscissa" about 50 years ago. :frown:
 
Yes that might be a possible reason. Thanks tiny-tim :smile:
 

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