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Area enclosed by line and curve - integration

  1. Nov 14, 2006 #1
    Hi guys,

    I need some help on this. It is in the integral section so I am assuming you use integrals for this. Can someone point me in the right direction.

    Find the total area enclosed by the line x = -3 and the curve x = 2y - y^2
     
  2. jcsd
  3. Nov 14, 2006 #2
    You have to take [tex] \int_{a}^{b} f(y) - g(y) \; dy [/tex] where [tex] f(x) [/tex] is the greater function. To get the limits of integration set [tex] - 3 = 2y-y^{2} [/tex]
     
    Last edited: Nov 14, 2006
  4. Nov 16, 2006 #3
    so let me see if I understand this correctly.
    [tex] \int_{-1}^{3} (2y-y^{2}) - (-3) \; dy [/tex]

    is that correct?
     
    Last edited: Nov 16, 2006
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