Area enclosed by line and curve - integration

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SUMMARY

The discussion focuses on calculating the area enclosed by the line x = -3 and the curve defined by the equation x = 2y - y². The correct approach involves using the integral formula ∫[a to b] (f(y) - g(y)) dy, where f(y) represents the upper function and g(y) the lower function. The limits of integration are determined by solving the equation -3 = 2y - y², leading to the integral ∫[-1 to 3] (2y - y² + 3) dy for the area calculation.

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  • Understanding of definite integrals
  • Familiarity with quadratic functions
  • Knowledge of setting limits of integration
  • Basic skills in algebraic manipulation
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  • Study the properties of definite integrals
  • Learn how to find intersections of curves and lines
  • Explore applications of integration in calculating areas
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Students in calculus, mathematics educators, and anyone interested in applying integration techniques to find areas between curves and lines.

donjt81
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Hi guys,

I need some help on this. It is in the integral section so I am assuming you use integrals for this. Can someone point me in the right direction.

Find the total area enclosed by the line x = -3 and the curve x = 2y - y^2
 
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You have to take [tex]\int_{a}^{b} f(y) - g(y) \; dy[/tex] where [tex]f(x)[/tex] is the greater function. To get the limits of integration set [tex]- 3 = 2y-y^{2}[/tex]
 
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so let me see if I understand this correctly.
[tex]\int_{-1}^{3} (2y-y^{2}) - (-3) \; dy[/tex]

is that correct?
 
Last edited:

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