1. The problem statement, all variables and given/known data The title really says it all. Find the area of the region inside r=6sin(theta) but outside r=3. 2. Relevant equations 3. The attempt at a solution I first found the x values where the two curves intersect and came up with .52359877 and 2.61799388. I then integrated 6sin(theta) (or, -6cos(theta)) from .52359877 to 2.61799388. The answer I got was 10.3923, but that's incorrect.