Area of a parallelogram with vectors

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SUMMARY

The area of the parallelogram spanned by the vectors <0, 9, 6> and <−10, −6, −4> is determined using the cross product formula, A X B. The calculated cross product results in the vector <0, -60, 90>. To find the area, the magnitude of this vector must be computed, which is |AxB|. The final area is the length of the cross product vector, confirming that the area is a scalar quantity, not a vector.

PREREQUISITES
  • Understanding of vector operations, specifically cross products
  • Familiarity with vector notation in three-dimensional space
  • Knowledge of calculating the magnitude of a vector
  • Basic concepts of geometry related to parallelograms
NEXT STEPS
  • Learn how to compute the magnitude of a vector in three-dimensional space
  • Study the properties and applications of the cross product in physics
  • Explore examples of calculating areas of geometric shapes using vectors
  • Investigate the implications of vector direction in cross product results
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Students studying vector calculus, geometry enthusiasts, and anyone looking to understand the application of cross products in determining areas of parallelograms.

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Homework Statement


Determine the area of the parallelogram spanned by the vectors
< 0, 9, 6 > and < −10, −6, −4 >


Homework Equations


Area = A X B

The cross product of < 0, 9, 6 > and < −10, −6, −4 > = 0i - 60j + 90k

The Attempt at a Solution



I know the area is the cross product of A X B, but the examples that I have done did not have a k value. ex <3,-3,0> X <2,3,0> What do I do now that I have a k value?
 
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Area is a real number. Not a vector. It's |AxB|. You need to find the length of the cross product vector.
 
Thank you, I got it.
 

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