Vector problem: distance between a point and a line

  • Thread starter Thread starter Clara Chung
  • Start date Start date
  • Tags Tags
    Line Point Vector
Click For Summary
SUMMARY

The discussion focuses on calculating the distance from a point to a line using vector mathematics. The formula presented, d = |(a-b) x (p-b)| / |(b-a)|, is derived from the area of the parallelogram formed by vectors BA and BP. The solution involves equating the area of a triangle formed by vectors (b-a), (p-a), and (p-b) in two different ways to find the correct distance. The participants clarify the use of different sides of the triangle to arrive at the solution.

PREREQUISITES
  • Understanding of vector operations, specifically cross product and magnitude.
  • Familiarity with geometric interpretations of vectors in two-dimensional space.
  • Knowledge of triangle area calculations using vectors.
  • Basic proficiency in linear algebra concepts.
NEXT STEPS
  • Study vector cross product properties and applications in geometry.
  • Learn about calculating areas of triangles using vector methods.
  • Explore the geometric interpretation of distance from a point to a line in vector space.
  • Investigate advanced topics in linear algebra, such as vector projections and their applications.
USEFUL FOR

Students studying geometry, mathematics enthusiasts, and anyone interested in vector calculus and its applications in physics and engineering.

Clara Chung
Messages
300
Reaction score
13

Homework Statement


26.png


Homework Equations

The Attempt at a Solution


My answer is d = |(a-b)x(p-b)|/|(b-a|). I first find out the area of the parallelogram produced by BA and BP and divide the area by length AB to get the height. Why am I wrong?
 

Attachments

  • 26.png
    26.png
    19.7 KB · Views: 701
Physics news on Phys.org
You have a triangle formed by ##(\vec b - \vec a)##, ##(\vec p - \vec a)## and ##(\vec p - \vec b)##. Write its area in two different ways and set them equal.
 
  • Like
Likes   Reactions: Clara Chung
kuruman said:
You have a triangle formed by ##(\vec b - \vec a)##, ##(\vec p - \vec a)## and ##(\vec p - \vec b)##. Write its area in two different ways and set them equal.
I see. I can also use the side p-a and p-b. Thank you.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
Replies
11
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
5
Views
2K
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K