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Area of portion of this figure

  1. Jul 27, 2011 #1
  2. jcsd
  3. Jul 27, 2011 #2


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    welcome to pf!

    hi maan143! welcome to pf! :wink:

    Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
  4. Jul 27, 2011 #3


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    Is the point A supposed to be the vertex? If not, the problem is unworkable and if so the picture should show a slope of 0 at A.
  5. Jul 28, 2011 #4
    Thanx. for ur replies.

    mmm... actually I wanted to make it as simple as possible, so I drew this figure for easy understanding of the prob.

    okay! here's the link, www.youtube.com/watch?v=zVKf6hZfrhA&feature=related

    just seek upto 25:24
    why did he take 1/3 * 0.45fck * 0.57x
    Why not 1/6 * 0.45fck * 0.57x

    where, 0.45fck = 5 (in previous thread figure)
    0.57x = 6 (in previous thread figure)
    0.43x = 4 (in previous thread figure)

    and don't worry (consider) 'b' in the youtube video, coz we are considering only area (2-D)

    Now did I make the prob. clear to you guys and let me know, if I didn't .

    Thanx. again.
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