Area of portion of this figure

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  • Thread starter Thread starter maan143
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    Area Figure
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Discussion Overview

The discussion revolves around determining the area of a specific portion of a parabolic figure. Participants are exploring the mathematical approaches and reasoning behind the area calculation, referencing both a figure and a video for context.

Discussion Character

  • Exploratory
  • Mathematical reasoning

Main Points Raised

  • One participant seeks to find the area of a portion of a parabolic curve, providing a link to an image for reference.
  • Another participant requests clarification on what the original poster has attempted and where they are encountering difficulties.
  • A participant questions whether a specific point in the figure is the vertex of the parabola, suggesting that the problem may not be solvable if it is not.
  • The original poster expresses a desire for simplicity in their figure and references a video, asking why a particular area calculation uses a factor of 1/3 instead of 1/6, providing specific numerical values for context.

Areas of Agreement / Disagreement

There is no clear consensus among participants regarding the assumptions about the figure or the area calculation methods. Multiple viewpoints and questions remain unresolved.

Contextual Notes

Participants have not fully clarified the assumptions regarding the vertex of the parabola or the specific area calculation methods, leading to potential ambiguities in the problem setup.

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welcome to pf!

hi maan143! welcome to pf! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Is the point A supposed to be the vertex? If not, the problem is unworkable and if so the picture should show a slope of 0 at A.
 
Thanx. for ur replies.

mmm... actually I wanted to make it as simple as possible, so I drew this figure for easy understanding of the prob.

okay! here's the link, www.youtube.com/watch?v=zVKf6hZfrhA&feature=related

just seek upto 25:24
why did he take 1/3 * 0.45fck * 0.57x
Why not 1/6 * 0.45fck * 0.57x

where, 0.45fck = 5 (in previous thread figure)
0.57x = 6 (in previous thread figure)
0.43x = 4 (in previous thread figure)and don't worry (consider) 'b' in the youtube video, coz we are considering only area (2-D)Now did I make the prob. clear to you guys and let me know, if I didn't .

Thanx. again.
 

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