Area of portion of this figure

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The discussion revolves around calculating the area of a specific portion of a parabolic figure. The user seeks clarification on the methods used in a referenced video, questioning why a particular formula involving 1/3 is preferred over 1/6 for area calculation. Participants emphasize the importance of understanding the vertex's role in the problem and the need for clear visual aids. The user aims to simplify the problem for better comprehension. Overall, the conversation focuses on resolving the area calculation through collaborative input.
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welcome to pf!

hi maan143! welcome to pf! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Is the point A supposed to be the vertex? If not, the problem is unworkable and if so the picture should show a slope of 0 at A.
 
Thanx. for ur replies.

mmm... actually I wanted to make it as simple as possible, so I drew this figure for easy understanding of the prob.

okay! here's the link, www.youtube.com/watch?v=zVKf6hZfrhA&feature=related

just seek upto 25:24
why did he take 1/3 * 0.45fck * 0.57x
Why not 1/6 * 0.45fck * 0.57x

where, 0.45fck = 5 (in previous thread figure)
0.57x = 6 (in previous thread figure)
0.43x = 4 (in previous thread figure)and don't worry (consider) 'b' in the youtube video, coz we are considering only area (2-D)Now did I make the prob. clear to you guys and let me know, if I didn't .

Thanx. again.
 
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