- #1

- 3

- 0

## Homework Statement

I have a triangle ABC formed by vectors a = ( 2, 10, 25 ) and b = ( 5, 4, -2 ) attached at a point P.

And I have to calculate the area of the triangle ABC.

## Homework Equations

I'm pretty certain that I need to find the area of the parellogram and then half it.

So I need to find the cross product, by calculating the determinant.

## The Attempt at a Solution

Calculating the determinant I got

-120 i + 129 j - 42 k

so does this mean i square those and take the square root of them to find the area of the parellogram and then half it...

= 181.121

=> area of triangle = 90.56