Area Under Graphs: Finding Work Done

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Discussion Overview

The discussion revolves around understanding the concept of work done as represented by the area under force-distance graphs. Participants explore the differences between constant force and varying force scenarios, particularly focusing on triangular areas under the curve and the implications for calculating work done.

Discussion Character

  • Conceptual clarification
  • Mathematical reasoning

Main Points Raised

  • One participant describes the relationship between force and distance in a constant force scenario, noting that the area under the graph corresponds to work done as force x distance.
  • The same participant expresses confusion about a triangular area under a graph representing a varying force, questioning why work done is calculated as 1/2 force x distance instead of force x distance.
  • Another participant explains that work done can be represented as an integral of force over distance, suggesting that this integral corresponds to the area under the curve.
  • A further contribution emphasizes that the equation work = force x distance holds true regardless of the force's constancy, and discusses the concept of integration to find total work from incremental contributions of force over small distances.

Areas of Agreement / Disagreement

Participants generally agree on the principle that work done is related to the area under the force-distance graph, but there is some confusion regarding the application of this principle in cases of varying force, particularly with triangular areas.

Contextual Notes

The discussion highlights the need for clarity on the concept of integration and how it applies to calculating work done from varying forces, but does not resolve the confusion expressed by the initial participant regarding the triangular area calculation.

Who May Find This Useful

This discussion may be useful for students or individuals seeking to understand the relationship between force and work in physics, particularly in the context of graphical representations and integration concepts.

IQScience
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Okay, so I've got a question on graphs and areas under curves.

For example, a force-distance graph, with force on the y-axis and distance on the x-axis, where you find work done from that graph.
I understand that a constant force will produce a horizontal line on the graph, like so:

Force
|
|-------------
|
|
|___________distance

So the area under the line is just force x distance.
This matches the equation, work = force x distance.

But I'm having trouble understanding a proportional graph, or one that looks like a triangle, like this:

Force
|------/-----
|-----/-----
|----/------
|---/-------
|--/--------
|-/---------
|/_________distance

i.e. force increases at a constant rate.

To find work done from this, you find the area under the line, which is a triangle.
But this doesn't match the equation (work = force x distance) which is confusing me.
Why is it not force x distance like the equation?
Why is is 1/2 force x distance now?
I understand that this is because the area under the line is a triangle, but why is work done the area under the graph?
 
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You know that work done is ##\int{Fdx}## in one dimension and you know that integral is equal to the area under the curve so work done would be equal to the area under the curve.
 
What is the average force under the second diagram?

Remember, work = force * distance applies regardless of the amount of force or the distance over which it acts. If you understand the concept of integration, you will see that to determine the work under a force-distance diagram, you are calculating incrementally all of the little bits of work done by a constant force acting over a small distance. In the limit, as these small increments of distance go to zero, then the total work is found.
 
Ahhhhh, I see, that makes sense.

Thank you very much :smile:
 

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