Rajini
- 619
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Hello all,
I need to know the area under the following curve (Lorentzian type):
f(x)=\frac{I(\Gamma/2) ^2}{(x-x_0)+(\Gamma/2) ^2}=\frac{I\Gamma ^2}{4(x-x_0)+\Gamma ^2}.
In the above Loretzian function we all know that \Gamma is fullwidth at half maximum, x_0 is peak's centre and I is the height.
What is the area under Lorentzian function shown above (for x_0=0)?
\int f(x)=?.
please help me!
thanks
I need to know the area under the following curve (Lorentzian type):
f(x)=\frac{I(\Gamma/2) ^2}{(x-x_0)+(\Gamma/2) ^2}=\frac{I\Gamma ^2}{4(x-x_0)+\Gamma ^2}.
In the above Loretzian function we all know that \Gamma is fullwidth at half maximum, x_0 is peak's centre and I is the height.
What is the area under Lorentzian function shown above (for x_0=0)?
\int f(x)=?.
please help me!
thanks