Area under the following curve (Lorentzian type)

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SUMMARY

The discussion centers on calculating the area under a Lorentzian curve defined by the function f(x) = I(Γ/2)² / [(x - x₀) + (Γ/2)²]. The parameters involved include Γ (full width at half maximum), x₀ (peak's center), and I (height). The specific case discussed is for x₀ = 0, leading to the integral of the function. The area under the Lorentzian curve can be determined using the integral formula provided, which simplifies to a logarithmic expression.

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  • Understanding of Lorentzian functions and their properties
  • Knowledge of integral calculus, specifically definite integrals
  • Familiarity with the concept of full width at half maximum (FWHM)
  • Basic logarithmic functions and their applications
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  • Investigate the relationship between FWHM and spectral line shapes
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Rajini
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Hello all,
I need to know the area under the following curve (Lorentzian type):
f(x)=\frac{I(\Gamma/2) ^2}{(x-x_0)+(\Gamma/2) ^2}=\frac{I\Gamma ^2}{4(x-x_0)+\Gamma ^2}.
In the above Loretzian function we all know that \Gamma is fullwidth at half maximum, x_0 is peak's centre and I is the height.
What is the area under Lorentzian function shown above (for x_0=0)?
\int f(x)=?.
please help me!
thanks
 
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\int \frac {k}{b(x-a) + c}\, dx = \frac {k \ln(bx - ba + c)}{b} +C
 


Hello Kurtz,
thanks for your help!..

bye
 

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