Arithmetic in Mathematical Fields (in particular GF(2^8) )

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In the discussion about finding the determinant of a matrix in GF(2^8), participants clarify that GF(256) is a finite field, distinct from the ring of integers modulo 256. The confusion arises regarding whether to use mod 255 or mod 256 for the determinant, especially since the determinant can be negative. It is emphasized that calculations in GF(256) involve polynomials with coefficients from Z_2, and the operations should be performed modulo a primitive polynomial of degree 8. Ultimately, the focus is on understanding the structure of the field and the correct approach to handle negative determinants.
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Homework Statement



* note that I meant fields in the abstract mathematical sense, notphysical (i.e. electric) fields! *

Finding the determinant of a matrix in GF(28)

I want to know if it is using mod 256 or mod 255 in the field of GF(28)

Homework Equations



Just math

The Attempt at a Solution



I found the determinant of a matrix no problem. Everything in between is all good. What I want to know is that in the field of GF(28), am I taking the number mod 255 or mod 256?

I know that there are a total of 256 elements in the field, but I'm just not sure which mod to take for the final answer, since it is a negative determinant.
 
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Modulo 256. The possible moduli are 0, 1, 2, ..., 255, the possible remainders when you divide by 256.
 
thanks Mark
 
Noooo! You're both wrong. GF(256) is a finite field, an extension field of GF(2). It is not not the same as the ring Z/256 of integers modulo 256.
 
Hurkyl, I agree that GF(256) is a finite field, but if we're both wrong, then how would I handle whole negative numbers?
 
You are just computing Mod 2 with the numbers. The elements are polynomials, the coefficients are from Z_2 and you're computing Modulo some primitive polynomial over Z_2 of 8th degree.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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