Arrangement of items after removing some of the items

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Homework Help Overview

The problem involves a bag containing 4 red cubic blocks and 3 yellow cubic blocks, from which 5 blocks are randomly removed and arranged in a line. The original poster suggests that the number of arrangements is 8, but expresses confusion regarding their calculations, which yield a fractional result.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants question whether blocks of the same color are indistinguishable and discuss the implications of this assumption on the arrangement calculations. There is also a focus on the need for logical reasoning behind the calculations rather than just applying formulas.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the problem statement and exploring different interpretations of how the blocks can be arranged based on the colors chosen. Some guidance has been offered regarding the necessity of logical reasoning in the approach.

Contextual Notes

There is uncertainty regarding the completeness of the problem statement, as participants note that the provided information may not lead to the suggested answer of 8. The discussion includes considerations of different combinations of red and yellow blocks that could affect the total arrangements.

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Homework Statement


A bag contains 4 red cubic blocks, 3 yellow cubic blocks, . Five cubic blocks are removed randomly from the bag and arranged in line . How many arrangements are possible?

the ans is 8 .

my working is 7P5/(4! X 3!) =17.5 .

my ans is rather weird.


Homework Equations





The Attempt at a Solution

 
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Are we to assume that blocks of the same color are indistinguishable?
 
desmond iking said:

Homework Statement


A bag contains 4 red cubic blocks, 3 yellow cubic blocks, . Five cubic blocks are removed randomly from the bag and arranged in line . How many arrangements are possible?

the ans is 8 .

my working is 7P5/(4! X 3!) =17.5 .

my ans is rather weird.


Homework Equations





The Attempt at a Solution


The number of arrangements cannot possibly be 17.5; it cannot be fractional.

Instead of just writing down some formulas, you need to explain the logic, so that we are in a position to assist you. If your thinking is "off", we need to know first what it is before we can put you on the right track.
 
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Ray Vickson said:
The number of arrangements cannot possibly be 17.5; it cannot be fractional.

Instead of just writing down some formulas, you need to explain the logic, so that we are in a position to assist you. If your thinking is "off", we need to know first what it is before we can put you on the right track.

my reasoning is first i choose 5 blocks from the 7 blocks. then since there 're 4 same colour red and 5 same colour yellow, so i divide it by 4! X 3!
 
You need to provide more information. Is that really the full problem statement? I don't see an interpretation that yields the answer 8. For example, if you end up choosing 4 red and 1 yellow, I'd say that 5 arrangements are possible, and if you end up choosing 3 red and 2 yellow, I'd say that 10 arrangements are possible.
 

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