Assigning Polarities and using them in KVL equation, circuits

  • Context: Undergrad 
  • Thread starter Thread starter wahaj
  • Start date Start date
  • Tags Tags
    Circuits Kvl
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 3K views
wahaj
Messages
154
Reaction score
2
I am having trouble understanding how to assign polarities to voltage when it goes through components of a circuit and how those polarities determine the sign of the quantities I put in the KVL equation. Attached is a picture of a circuit. The points where polarity matters are labeled 1-14. I am trying to find the voltage of battery 1/2. I know how to assign polarities to batteries but are there any rules I should obey when assigning polarities to resistors? Also what happens to voltage when batteries are connected like battery 1/2 and battery 3/4 in the picture? Also when putting quantities in the kvl equation how can I determine which quantity is positive and which is negative? and lastly what role do polarities play when solving circuit problems?
 

Attachments

  • Circuit1.jpg
    Circuit1.jpg
    22.2 KB · Views: 592
Physics news on Phys.org
It doesn't matter as long as you are consistent. If you guess wrong all that will happen is that when you solve the system of equations one of the voltages will be negative.
 
if you assign all +/- pairs consistently going around the loop, the sum of the voltages must equal zero.

but if you assign the polarities as you see fit, then, going around the loop (either clockwise or counter-clockwise), then KVL says that the sum of the voltage rises equals the sum of the voltage drops.

both versions say the same thing.
 
ok so when putting the voltages in the equation how do I distinguish between the two different polarities? another way to say this is how to I know when the voltage drops and when the voltage rises?
 
Last edited: