I had recently received an exam back rom my kinematics unit in my physics course, this is the only question that I answered and was incorrect. I was wondering if someone could assist me on what steps I am missing. The correct answer is 3.2m, but I can't figure out how to get to it. A ball is launched from a cliff with and initial velocity of 15 m/s at an angle of 40o above horizontal. If the ball lands 26 m away, determine the height of the cliff. Horizontal V=cos40(15) v=11.5 T=d/v T=26/11.5 T=2.26s Vertical V1=sin40(15) v1=9.64 d=v1t+1/2at^2 d=9.64(2.26)+1/2(-9.8)t^2 d=-2.5m Any feedback would be greatly appreciated.