- #1
TheKovac
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Homework Statement
A parachutist is falling vertically with a uniform speed of 12 m/s. At the instant he is 50m above the ground, he drops a coin. (Ignore Air Resistance)
A) What is the seed with which the coin strikes the ground?
b) How long does it take for the coin to reach the ground
C) WHAT IS THE TIME DIFFERENCE BETWEEN THE COIN AND PARACHUTIST REACHING THE GROUND?
Homework Equations
v^2 = u^@ + 2ax
x=Ut+0.5at^2
x=0.5(u+v)t
v=u+at
The Attempt at a Solution
a)
=> v^2 = 12^2 +2(9.8)(50)
final velocity of coin= 33.53m/s RIGHT
b)
x=ut + 0.5at^2
50= 12t +0.5(9.8)t^2
4.9t^2 +12t -50=0
time for coin to reach ground = 2.19s
c) =?
Is this question able to be solved, with the current data, because I believe I would need mass or total displacement to correctly work the answer.
Can someone please help me on how to go about answering such a question as this.
Kindest Regards,
TheKovac