1. The problem statement, all variables and given/known data Suppose that an asteroid traveling straight toward the center of the earth were to collide with our planet at the equator and bury itself just below the surface. What would have to be the mass of this asteroid, in terms of the earth's mass M , for the day to become 26.0% longer than it presently is as a result of the collision? Assume that the asteroid is very small compared to the earth and that the earth is uniform throughout. 2. Relevant equations Conservation of angular momentum: Linitial = Lfinal 3. The attempt at a solution ωfinal = (0.74)ωinitial (This makes the final speed 26% slower than the original) Linitial = Lfinal Iinitialωinitial = Ifinalωfinal Iinitialωinitial = Ifinal(0.74)ωinitial (ωinitial cancel out) (2/5)MR2 = ((2/5)MR2 + mR2)(0.74) (R2's cancel out) (2/5)M = ((2/5)M + m) (0.74) (Distribute the 0.74) (2/5)M = ((1.48/5)M + 0.74m) 0.74 m = (2/5)M - (1.48/5)M 0.74m = M((2/5) - (1.48/5)) 0.74m = 0.104M m = 0.141M This answer is m = 0.104M which is on the right side of the second to last line (0.74m = 0.104M), but I still have the 0.74 on the left side. Where is my mistake?