• Joe91090
In summary, the astronaut weighs 89 kg and is drifting through space at a constant velocity. After turning to look at Earth for several seconds, the astronaut is 43.8m behind the ship and has a velocity of 0.17 m/s. To return to the ship, the astronaut throws a wrench with a mass of 0.690 kg and a speed of 21.9 m/s. Using the equation mv1=mv2, the astronaut calculates a velocity of 0.17 m/s and a time of 7.43 seconds to return to the ship. However, upon reflection, this answer does not seem reasonable. The correct calculation is time=distance/velocity, resulting in a longer time needed to
Joe91090

## Homework Statement

An 89 kg astronaut is working on the engines of a spaceship that is drifting through space with a constant velocity. the astronaut turns away to look at the Earth and several seconds later is 43.8m behind the ship, at rest to relative to the spaceship. The only way to return to the ship without a thruster is to throw a wrench directly away from the ship. The wrenches mass is .690 kg, and the astronaut throws the wrench with a speed of 21.9 m/s.

How long does it take the astronaut to return to the ship ?

mv1 = mv2

## The Attempt at a Solution

i tryed (.690)(21.9) = (89)(x) and got the velocity of the astronaut .17 m/s so i multiplied that by the distance 43.8m and got 7.43 s is this correct ??

First part seems good but I think you've got the last part muddled up.

If the speed of the astronaut's recoil is 0.17m/s then you need to divide the distance by this number to find the time.
speed = dist/time

time = dist / speed

If you reflect on your answer you should see that it isn't reasonable to cover 43m in 7 seconds moving at less than a metre per second.

of course ! thanks a lot

time = distance / velocity...

edit: oh nevermind, a lil' too late

Last edited:

"Astronaut Momentum: Return to Ship in 7.43s" is a scientific experiment that involves an astronaut returning to their spaceship in a specific amount of time, 7.43 seconds, while maintaining their momentum.

## 2. Why is this experiment important?

This experiment is important because it can help scientists understand how to efficiently move in space and maintain momentum. This knowledge can be crucial for future space missions and space exploration.

## 3. How is this experiment conducted?

This experiment is conducted by having the astronaut in a weightless environment and giving them a specific amount of time, 7.43 seconds, to return to their spaceship while maintaining their momentum. The astronaut may use various techniques, such as using their arms and legs to push off objects, to achieve this goal.

## 4. What are the potential results of this experiment?

The potential results of this experiment include determining the most efficient ways to move and maintain momentum in space, which can aid in future space missions. It can also potentially lead to advancements in space technology and equipment.

## 5. Are there any risks involved in this experiment?

Since this experiment involves an astronaut moving in a weightless environment, there is a risk of injury if proper precautions are not taken. However, safety measures and protocols are put in place to minimize these risks and ensure the well-being of the astronaut.

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