How Long Does It Take Astronaut Jane to Drift Back to Her Spaceship?

Mowgli
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Homework Statement



Astronaut Jane's lifeline to her spaceship comes loose and she finds herself stranded, "floating" 75.0m from the spaceship. She throws her 2.00kg wrench at 20.0m/s in a direction away from the ship. If she and her spacesuit have a combined mass of 175kg how long does it take her to coast back to the spaceship?



Homework Equations





The Attempt at a Solution



This one I am so lost about...

Do I use the equation: (Mass of Suit x Mass of Jane) Initial Velocity + Mass of wrench (Initial Velocity) = (M of Suit + M of Jane) (V 1 + M of wrench (V 1 of wrench)

Therefore = (175kg) 0 + 2kg (0) = (175kg) (final velocity + 2kg (20.0m/s)
 
on Phys.org
All is good to this point.
 
Do I have to factor in the fact that she floated 75 m away?
 
Mowgli said:
Do I have to factor in the fact that she floated 75 m away?

That does not influence conservation of momentum.

You only need the distance to find the time it takes to get back to the ship.
 
Mowgli said:

Homework Statement




Therefore = (175kg) 0 + 2kg (0) = (175kg) (final velocity + 2kg (20.0m/s)

then 0=175(final velocity) + 40

final velocity = -40/175
= -0.23 m/s ??
 
Mowgli said:
then 0=175(final velocity) + 40

final velocity = -40/175
= -0.23 m/s ??

Looks okay so far.
 
what else needs to be done?
 
Mowgli said:
what else needs to be done?
You need to find out how much time it takes for someone to travel 75.0 m when traveling at a speed of 0.229 m/s.
 

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