Astrophysics: Finding the mass of a hidden star in a binary system

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SUMMARY

The discussion focuses on calculating the mass of an unseen binary companion to a low mass main sequence star, based on observed sinusoidal velocity variations of 500 km/s over a period of 10 hours. The relevant equations include M1 + M2 = (4π²a³)/(GP²) and M1r1 = M2r2, where 'a' represents the radius of the orbit. The initial calculation yielded M1 = 1.30x10^13 kg, but the assumption that the hidden object is significantly more massive than the observed star was questioned. A more accurate approach involves calculating the mass ratio and utilizing the known mass of the observed star for estimation.

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Homework Statement



The spectral lines in a low mass main sequence star show sinusodal velocity variations with an amplitude of 500 km/s and a time period of 10 hours

calculate a lower limit to the mass of the unseen binary companion


Homework Equations



M1 + M2 = [tex]\frac{4\pi^2a^3}{GP^2}[/tex]

M1r1 = M2r2

a = r1 + r2

The Attempt at a Solution



The redshifted and blueshifted spectral lines show that the star is traveling at 500km/s

in a time period of 10 hoiurs (= 36 000 seconds)

Distance traveled in 1 orbit = 18 000 000 km

radius of orbit = [tex]\frac{18 000 000}{2\pi}[/tex] = 28274334 km

assume that the hidden object is much more massive.

so a = radius of this orbit = 28274334000 m

M1 >> M2 therefore r1 << r2

M1 = [tex]\frac{4\pi^2r^3}{GP^2}[/tex]

M1 = 1.30x10^13 kg

this is wrong,

think i may have made a mistake when i said that the hidden object is much more massive, can this be solved without making an assumption?
 
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I think you can calculate ratio of both masses, then use information about mass of the observed star ("low mass main sequence star") to estimate mass of the other one. But that's just intuition, I can be easily wrong.
 

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