At what angle does the light leave the glass?

AI Thread Summary
A ray of light strikes a rectangular block of glass at a 30.0° angle of incidence. Using Snell's Law, the initial calculation yields an angle of refraction of 28.359° at point A. After further consideration, the correct angle of refraction at point B is determined to be 53.13°. The calculations involve the refractive indices of glass (n = 1.52) and the surrounding liquid (n = 1.60). The final answer for the angle at which the ray leaves the glass is confirmed as 53.13 degrees.
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Homework Statement


The drawing shows a rectangular block of glass (n = 1.52) surrounded by a liquid with n = 1.60. A ray of light is incident on the glass at point A with a 30.0° angle of incidence. At what angle does the ray leave the glass at point B?

http://edugen.wiley.com/edugen/courses/crs1507/art/qb/qu/c26/ch26p_18.gif


Homework Equations


n1sintheta1 = n2sintheta2



The Attempt at a Solution


(1.52)sin(30) = (1.6)sintheta2
theta2 = 28.359

I have no idea what I did wrong.. should the angle be negative??
 
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theta2 = 28.359
This is the angle of refraction at point A. From that find the angle of incidence on the surface containing point B.
 
Ohh, is this right then..?

sintheta2 = (1.6) sin30/1
theta2 = 53.13
 
Nevermind, I got it :] 53.13 degrees is the answer. Thanks!
 
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