An object is placed in front of a convex mirror with a 65 cm radius of curvature. A virtual image half the size of the object is formed. At what distance is the object from the mirror?
1/p + 1/q = 1/f
The Attempt at a Solution
I have tried this problem several times different ways and cannot get the correct solution. I tried it this way.
focal length = Radius of curvature/2 = -32.5 cm (negative because convex mirror
virtual image = 1/2 object = -q
object = + p
I obtained 16.25 using equation 1/p -1/32.5 = -1/32.5, but it is wrong, as well as -16.25. Any help would be great.