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Moved from another forum, so homework template missing

Hello, I've been trying to answering this question but my answer is always wrong.

Two point charges, -9.10

(a) At what point along the x axis is the electric field zero?

What i did: i figured that the point should be on the left of the first charge, so before x=0 (should be negative).

Then i resolve E1 + E2 =0

kQ1/r^2 + kQ2/r^2 =0

(-8,19*10^4)/(x^2) + (1,916*10^5)/((x+8)^2) = 0

(8,19*10^4)/(x^2) = (1,916*10^5)/((x+8)^2)

1.916*10^5*(x^2) = 8,19*10^4 ((x+8)^2)

Then i develop and get x1= 1.51*10^1 or x2= -3.16

What am i doing wrong??

Thank you for your help!

Two point charges, -9.10

*μC*and 21.29*μC*, are placed at*x*= 0*cm*and*x*= 8.00*cm*, respectively.(a) At what point along the x axis is the electric field zero?

What i did: i figured that the point should be on the left of the first charge, so before x=0 (should be negative).

Then i resolve E1 + E2 =0

kQ1/r^2 + kQ2/r^2 =0

(-8,19*10^4)/(x^2) + (1,916*10^5)/((x+8)^2) = 0

(8,19*10^4)/(x^2) = (1,916*10^5)/((x+8)^2)

1.916*10^5*(x^2) = 8,19*10^4 ((x+8)^2)

Then i develop and get x1= 1.51*10^1 or x2= -3.16

What am i doing wrong??

Thank you for your help!