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## Homework Statement

a 8kg steel ball strikes a wall with a speed of 11.7 m/s at an angle of 35.3 degrees with the normal to the wall. it bounces off with the same speed and angle as shown in the picture.

http://img405.imageshack.us/img405/7733/asdfkf7.jpg [Broken]

If the ball is in contact with the wall for 0.297 seconds, what is the magnitude of the average force exerted on the ball by the wall? Answer in N

## Homework Equations

## The Attempt at a Solution

Ft = mv

F(0.297) = 8 * 11.7

F = 315.15 kg* m/s^2 or N but thats if its a linear problem

Angle wise

Horizontal speed of 11.7 m/s

Cos 35.3 = x / 11.7

x = 9.549 m/s

Extra info

Vertical speed of 11.7 m/s

sin 35.3 = y / 11.7

y = 6.761 m/s

Ft = mv

F(0.297) = 8 * 9.549 m/s

F = 257.2069 N

is that right?

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