Average/RMS Values of a Rectangular and Ramp Function

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SUMMARY

The discussion focuses on calculating the RMS (Root Mean Square) and average values of a rectangular and ramp function. The RMS value for the given current is calculated as Irms = 6/√3, resulting in 3.46 mA. The average value is derived from the peak value, yielding an average of 3 mA. The process involves squaring the instantaneous values, averaging them over one cycle, and then taking the square root of that average.

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Homework Statement


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Homework Equations


Irms = [itex]\frac{I<sub>m</sub>}{\sqrt{3}}[/itex]

The Attempt at a Solution


I'm lost on how to do a completely, whereas for b. I can find the Irms:
Irms = [itex]\frac{6}{\sqrt{3}}[/itex] = 3.46 mA
and the average, I'm guessing is 6/2 = 3 mA?

Thank you in advance!
 
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This is not an exercise you do in your head.

To find the RMS: you take the square root of ... the average value of ... the graph of one cycle of the waveform SQUARED.

So you draw a new graph, this time plotting instantaneous V2 vs. time
Then determine the area under that curve, and average it over the whole cycle.
Then take the square root of this average value.
 

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