Average/RMS Values of a Rectangular and Ramp Function

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ohdrayray
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Homework Statement


Two current waveform plots: left, a square wave of i(t) in mA alternating between 2 and -1 at t = 2, 4, 6, 8 ms; right, a sawtooth wave of i(t) in mA rising from 0 to 6 and resetting at t = 3, 6, 9 ms.


Homework Equations


Irms = [itex]\frac{I<sub>m</sub>}{\sqrt{3}}[/itex]

The Attempt at a Solution


I'm lost on how to do a completely, whereas for b. I can find the Irms:
Irms = [itex]\frac{6}{\sqrt{3}}[/itex] = 3.46 mA
and the average, I'm guessing is 6/2 = 3 mA?

Thank you in advance!
 
This is not an exercise you do in your head.

To find the RMS: you take the square root of ... the average value of ... the graph of one cycle of the waveform SQUARED.

So you draw a new graph, this time plotting instantaneous V2 vs. time
Then determine the area under that curve, and average it over the whole cycle.
Then take the square root of this average value.