# Find average and rms values of the waveform

## Homework Statement

The problem is located here http://www.chegg.com/homework-help/...ter-11-problem-26e-solution-9780073529578-exc

## Homework Equations

Rms=sqrt(1/T∫ from 0 to T of i(t)^2 DT )
Average= couldn't find an equation in book??

## The Attempt at a Solution

Ok so I did it on my own and I'm trying to figure out why in the solution that the person posted. Is i(t) only written for 3 time intervals 0<t<2, 2<t<3, and 3<t<5. Why is there not a 4th 5<t<6 where i(t) would equal -9 A. BTW this is the first part if it wasn't clear. Furthermore how is T=5 I would think it would be 2 as the square wave gets its maximum at -9 and it lasts for 2 and 3? Also what is the equation for average value of current? And more of the same on the second part of the problem why did they only do parts of the waveform?

Or is the solution incorrect

here is my work

#### Attachments

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gneill
Mentor
It's a repeating waveform. The average (or rms) over one cycle (period) is the same as over all periods. So you need to identify one period and work with that. Looks to me like the time interval from 0 to 3 would cover one period of the repeating signal (the interval from 3 to 6 is an exact repetition).

The mean is calculated in the same way that the mean is calculated for the rms, only the function isn't squared. That is,

$$mean = \frac{1}{T}\int_{t_o}^{t_f}i(t)dt$$

ah so T=3 then because it covers the time from its minimum to its max.

gneill
Mentor
T = 3 because it covers one period of the waveform. A period is the repeating unit of the waveform.

ok thanks