What is the average speed of a particle with given position and time data?

In summary: When v = 0 lies in the interval -5.06+6.10t=0t=5.06/6.10 which lies in the interval so you make the integral negative.
  • #1
Casimi
11
0

Homework Statement


The position of a particle as a function of time is given by x = (-5.06 m/s)t + (3.05 m/s2)t2. Calculate the average velocity of the particle from t = 0 to t = 1.20 s.
-1.40 m/s (this is correct, from my calculations)

2nd part: Calculate the average speed from t = 0 to t = 1.20 s


The Attempt at a Solution


I have tried this for hours and cannot arrive at the correct answer for the second part. I tried taking the total distance and dividing by the total time. Could someone please point me in the right direction to find average speed? I have even tried differentiation.

Any assistance would be appreciated. Thanks!
 
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  • #2
you can differentiate to get the velocity then take the integral of its absolute value then divide it by time
 
  • #3
I tried that but I am still not arriving at the correct answer. I arrive at a number far larger than it should be.

I cannot figure out what I am doing wrong.
 
  • #4
did you make sure to separate it into two integral when you integrated the absolute value one negative and one positive?
 
  • #5
(-5.06+6.10t) - that is my answer after differentiating. Integrating the absolute value, I have 5.06t+3.05t^2 with integral limits of 0 to 1.20. When I put the values in the integral, I get 9.456 and when divided by 1.2, I get 7.88 which is not the correct answer.
 
  • #6
I am saying as integral the absolute value
you must know if when v = 0 lies in your interval
-5.06+6.10t=0
t=5.06/6.10 this lies in the interval so you make the integral negative here and positive from it to 1.2
 
  • #7
Yes, I tried that and am still not arriving at the right answer. 5.06/6.10 will give .82. If I integrate from -5.06t+3.05t^2 [0 to .82] + 5.06t+3.05t^2 [.82 to 1.2] I am still going to get :
5.06t +3.05t^2 [0 to 1.2]? Please help me out.
 
  • #8
what you do is get the integral from 0 to .82 (5.06-6.1t)dt
+ the integral from .82 to 1.2 (-5.06 +6.1t)dt
 
  • #9
I came up with 2.51m/s but it is still showing as incorrect. Is this the solution that you arrived at?
 
  • #10
did you divide it by the time?
 
  • #11
Thank you! You just saved my grade!
 

What is the definition of average speed of a particle?

The average speed of a particle is the total distance traveled divided by the total time taken to travel that distance. It is a measure of the overall speed of a particle over a certain period of time.

How is average speed of a particle different from instantaneous speed?

Instantaneous speed refers to the speed of a particle at a specific moment in time, while average speed takes into account the entire duration of the particle's motion.

What units are used to measure average speed of a particle?

The most commonly used units for average speed of a particle are meters per second (m/s) or kilometers per hour (km/h). However, any unit of distance over time can be used as long as they are consistent.

Can the average speed of a particle be negative?

Yes, the average speed of a particle can be negative if the particle is traveling in the opposite direction of a chosen reference point. For example, if a particle moves 10 meters east and then 5 meters west, its average speed would be negative since the net displacement is -5 meters.

How is average speed of a particle related to velocity?

While average speed is a scalar quantity, velocity is a vector quantity that takes into account the speed and direction of a particle. Average speed is the magnitude of the average velocity vector.

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