Average speed of the gasoline as it leaves the nozzle?

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Homework Help Overview

The problem involves calculating the average speed of gasoline as it exits a nozzle, given the time taken to fill a gas tank and the dimensions of the nozzle. The subject area includes fluid dynamics and flow rate concepts.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the flow rate equation and its application, with some questioning the units involved. There is also exploration of the relationship between volume, area, and velocity in the context of fluid flow.

Discussion Status

Some participants have provided guidance on relevant equations and concepts, while others express confusion about the application of these principles. The discussion is active, with various interpretations and approaches being explored.

Contextual Notes

There is mention of a specific answer from a textbook, which raises questions about the derivation of that result. Additionally, some participants indicate uncertainty regarding the use of calculus in this context.

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Homework Statement


It takes 2 minutes to fill a gas tank with 40 liters of gasoline. If the nozzle is 1cm in radius, what is the average speed of the gasoline as it leaves the nozzle?


Homework Equations


A1V1=A2v2 or 1/2pv^2 + pgh+p=constant


The Attempt at a Solution


I don't really know were to start I have the volume of the tank as being .04m^3 I am not sure what to do next.
 
Last edited:
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You want the flow rate equation.

Q=v*A

Where Q = flowrate in cm^3/s and A is the cross-sectional area.
 


Why is the flow rate in cm^3/s wouldn't it be squared because of area.
A would be = to 3.14159265*10^-4
 


Also the books says the anwser is 1.1 meters a second i just don't know how it got to that
 


Volume V = X *A
V/t = X/t*A = v*A, where v is the velocity of the liquid flow through the nozzle.
 


is that calculus because I haven't been taught how to use or apply it to these types of problems.
 


NO. Not at all.
In the problem what is flow rate V/t?
If you freeze the outflow of one second, whose length is L and area of cross section is A, what is the volume of the liquid?
(L/one second) is the average velocity of out flow.
 


the volume is .04m^3, cross sectional area is .01^2*pi
 


dQ/dt = Volume/time. What is the time taken to fill the tank?
Velocity = (dQ/dt)/Area.
 
  • #10


Thanks i got it for some reason i couldn't get to that equation before but now i get it sorry for taking up your time.
 
  • #11


It is OK.
 

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