Average Upward Force on Amusement Ride Rider

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Homework Help Overview

The problem involves an amusement park ride that accelerates riders upward from rest to a speed of 50.0 m/s over a duration of 7 seconds. The weight of the rider is given as 1120 N, and the task is to determine the average upward force exerted by the seat on the rider while ignoring air resistance.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the initial and final velocities, with some confusion about the definitions of these terms. There are attempts to calculate acceleration and net force, with questions about the correct application of formulas.

Discussion Status

Some participants have provided calculations for acceleration and net force, while others question whether the correct forces are being considered, particularly the role of gravity. There is no explicit consensus on the correctness of the calculations or the next steps to take.

Contextual Notes

Participants note the absence of air resistance in the problem and emphasize the importance of considering gravitational force in their calculations. There is uncertainty regarding the proper approach to finding the average force exerted by the seat.

randomss444
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Homework Statement



An extreme amusement park ride accelerates its riders upward from rest at 50.0 m/s in 7 seconds. Ignoring air resistance, what average upward force does the seat exert on a rider who weights 1120N?

t = 7.00s
v = 50.0 m/s
Mass = 114.285
mg = 1120N

Homework Equations



∑F= ma

The Attempt at a Solution



I am not sure of that v is vi or vf.

I know my first step needs to be to solve for acceleration I just do not know how to do it given the information that I have.


Thanks
 
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randomss444 said:

The Attempt at a Solution



I am not sure of that v is vi or vf.

I know my first step needs to be to solve for acceleration I just do not know how to do it given the information that I have.

They told you this:

randomss444 said:
An extreme amusement park ride accelerates its riders upward from rest at 50.0 m/s in 7 seconds.

So the riders go from rest to a final velocity of 50 m/s in 7 seconds. (Initial is at rest, so vi=?)
 
Okay so how would I solve for vi?

could I use v = x/t to find then displacement

and then use x= 1/2(vi+vf)t to solve for vi

?

If do that then the answer comes out to be vi =2 and that does not seem right
 
Initial is at rest

In other words, intially it has zero velocity.

That being said, what's vi?
 
vi = initial velocity


Okay so we got
vf =50
vi=0
t =7.00s
m=114.2857143
mg=1120n

so we find acceleration by using vf=vi+at

50=0+7a
a=7.142857143

so we can find ∑E= ma

∑E = (114.2857143)(7.142857143)
∑E = 816.3265307

Is that right?
And would that be the final answer?
 
You're missing all your units in all of your calculations, but other than that the answer looks right. (Unless I made a mistake somewhere :S)
 
I'm not sure if that is correct. what you found is average acceleration from which you determined average net force, when instead you should be looking for is the average force exerted by the seat on the person. Are there other forces acting on the person you may have to consider?
 
The only one I can think of is gravity because it says to ignore air resistance.

So what should my next step be then and how do you find average force exerted by something?
 
randomss444 said:
The only one I can think of is gravity because it says to ignore air resistance.

So what should my next step be then and how do you find average force exerted by something?

gravity is always there, but since the person is sitting on the seat, there will something reaction wouldn't there?
 

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