B-field question Lorentz's force

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    B-field Force
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Homework Help Overview

The discussion revolves around a problem involving the Lorentz force acting on a charged particle in a magnetic field, specifically focusing on the motion of an electron and its kinetic energy. Participants explore the implications of the magnetic force, gravitational effects, and the nature of circular motion in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the balance of forces acting on the electron, questioning the role of gravity compared to the Lorentz force. There are attempts to derive expressions for velocity and kinetic energy, with some participants exploring the relationship between radius and motion. Questions arise about the nature of forces acting parallel to the motion and the implications of circular versus straight-line motion.

Discussion Status

The discussion is active, with participants providing various insights and calculations related to the problem. Some guidance has been offered regarding the nature of the Lorentz force and its implications for kinetic energy, but there remains a lack of consensus on certain interpretations and calculations.

Contextual Notes

Participants note that the problem may involve assumptions about the magnetic field's influence and the initial conditions of the electron's motion. There are also references to specific values and relationships that may not be fully clarified, such as the radius of the circular path and the nature of the forces involved.

  • #31
Ah Yes, the m lol
 
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  • #32
Are we squared away?

You should be able to give a numerical answer.
 
  • #33
a) 1.79 x 10^-8s

b) 5.63 x 10^-18J

Unless I made a mistake typing in my numbers.Sammy, I also noticed that you could do this

The arc length is \pi (2.00 \times 10^-2)

The speed is then

\frac{\pi (2.00 \times 10^-2)}{1.79 \times 10^-8}

Then I also get the same KE!
 
  • #34
Also, Sammy, when I calculated the velocity I used the average velocity formula and I forgot to divide it by 2. I should have used the change in velocity. My question, how come they don't give the same answer?
 
  • #35
The speed doesn't change.
 

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