SammyS Staff Emeritus Science Advisor Homework Helper Messages 11,987 Reaction score 1,584 Mar 29, 2011 #32 Are we squared away? You should be able to give a numerical answer.
flyingpig Messages 2,574 Reaction score 1 Mar 29, 2011 #33 a) 1.79 x 10^-8s b) 5.63 x 10^-18J Unless I made a mistake typing in my numbers.Sammy, I also noticed that you could do this The arc length is [tex]\pi (2.00 \times 10^-2)[/tex] The speed is then [tex]\frac{\pi (2.00 \times 10^-2)}{1.79 \times 10^-8}[/tex] Then I also get the same KE!
a) 1.79 x 10^-8s b) 5.63 x 10^-18J Unless I made a mistake typing in my numbers.Sammy, I also noticed that you could do this The arc length is [tex]\pi (2.00 \times 10^-2)[/tex] The speed is then [tex]\frac{\pi (2.00 \times 10^-2)}{1.79 \times 10^-8}[/tex] Then I also get the same KE!
flyingpig Messages 2,574 Reaction score 1 Mar 29, 2011 #34 Also, Sammy, when I calculated the velocity I used the average velocity formula and I forgot to divide it by 2. I should have used the change in velocity. My question, how come they don't give the same answer?
Also, Sammy, when I calculated the velocity I used the average velocity formula and I forgot to divide it by 2. I should have used the change in velocity. My question, how come they don't give the same answer?
SammyS Staff Emeritus Science Advisor Homework Helper Messages 11,987 Reaction score 1,584 Mar 29, 2011 #35 The speed doesn't change.