Time in Air for Ball Rolling Down a Ramp

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SUMMARY

The discussion focuses on calculating the time a ball is in the air after rolling down a ramp. The ball rolls down a 0.700m ramp and takes 0.750 seconds to reach the bottom, hitting a mark 1.70m away on the x-axis. Two primary methods for finding the initial velocity are proposed: calculating average velocity based on ramp length and time, or using the conservation of energy principle, equating potential energy loss to kinetic energy gain. The uniform acceleration of the ball is emphasized as a crucial factor in determining its velocity upon leaving the ramp.

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Homework Statement



A ball is placed 0.700m from the end of a declining ramp and rolls down the ramp in 0.750s. The marble is also 0.175m from the horizontal. The ball hits a mark on the floor that is 1.70m from the bottom of the ramp on the x-axis. What mount of time is the ball in the air after leaving the ramp?

Homework Equations





The Attempt at a Solution


Can't find initial velocity.
 
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Seems like a couple of approaches are available: one is to simply find the average velocity from the length of the ramp anf the time spent. Since acceleration is uniform the velocity as it leaves the ramp is twice that (initial velocity is zero).

The other is to equate potantial energy loss with kinetic energy gain while on the ramp.

In other words, mgh=1/2mv^2

From there you need to know the angle of the ramp. Then resolve the velocity in the x direction. This help?
 
The velocity,as it leaves the ramp, is twice what? The calculated velocity of distance/time?
 
Yep. The reason is that the acceleration is uniform. Otherwise this isn't true.
 

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