Ball Rolls off of a circle :O PROBLEM

  • Thread starter Thread starter Plutonium88
  • Start date Start date
  • Tags Tags
    Ball Circle
Click For Summary
A ball begins rolling on a circle from rest and eventually disconnects at a certain height. The discussion revolves around applying conservation of energy and centripetal force equations to determine the point of disconnection. The user is unsure about the relationship between forces at the moment of ejection and is seeking guidance on how to find the necessary angle for calculations. Key insights suggest that the ball will detach when its velocity exceeds the required centripetal velocity to maintain circular motion. Understanding the forces acting on the ball is crucial for solving the problem effectively.
Plutonium88
Messages
173
Reaction score
0
Ball Rolls off of a circle :O! PROBLEM!

So the problem is, a ball at zero velocity begins to roll on a circle. At a certain point the ball and the circle "DISCONNECT". There is a height x from the roof to the point it disconnects.

Given Information. Height X, Diameter D of circle, Vi=0, r=1/2D Mo=Mass Of The ball

http://postimage.org/image/a91pl12ll/

Relative Equations:
Conservation Of Energy
-Maybe centripetal force formula (Fc=Fg,ffr,)
-

My attempt:

i believe that at the point the ball ejects from the surface of the big circle, that the FN = 0 because it isn't going to be connected anymore... (CORRECT ME IF I'M WRONG)

- I feel like i don't have enough information, (obviously i do) but maybe i do not have the skills... I was wondering if some one could lead me in the right direction...

Now ET1=energy of the system at the top at rest
ET2=energy of the system at the point it detaches...

Et1=Et2
mgD=mgD-mgX+1/2mov2^2 -simplify

X = V2^2/2g

Now obviously I'm left with a problem with two unknowns... I've been drawing triangles all over this circle and trying to figure out how i can get an angle.. I figured out it makes an isosceles triangle if you connect the radius twice to the the point at which it detaches... But still i don't know how to get an angle.. I think i need to learn radiants(Or would that even help me)?

Anyways I'm stuck just need a little hint, please don't answer the whole problem
 
Last edited:
Physics news on Phys.org


Plutonium88 said:
So the problem is, a ball at zero velocity begins to roll on a circle. At a certain point the ball and the circle "DISCONNECT". There is a height x from the roof to the point it disconnects.

Given Information. Height X, Diameter D of circle, Vi=0, r=1/2D Mo=Mass Of The ball

http://postimage.org/image/a91pl12ll/

Relative Equations:
Conservation Of Energy
-Maybe centripetal force formula (Fc=Fg,ffr,)
-

My attempt:

i believe that at the point the ball ejects from the surface of the big circle, that the FN = 0 because it isn't going to be connected anymore... (CORRECT ME IF I'M WRONG)

- I feel like i don't have enough information, (obviously i do) but maybe i do not have the skills... I was wondering if some one could lead me in the right direction...

Now ET1=energy of the system at the top at rest
ET2=energy of the system at the point it detaches...

Et1=Et2
mgD=mgD-mgX+1/2mov2^2 -simplify

X = V2^2/2g

Now obviously I'm left with a problem with two unknowns... I've been drawing triangles all over this circle and trying to figure out how i can get an angle.. I figured out it makes an isosceles triangle if you connect the radius twice to the the point at which it detaches... But still i don't know how to get an angle.. I think i need to learn radiants(Or would that even help me)?

Anyways I'm stuck just need a little hint, please don't answer the whole problem

Something to contemplate..

If at any point the circle could magically disappear, the ball would become a projectile - following a parabolic path.

At the point where it leaves the circle, the potential parabolic path is presumably parallel to the circle at the time.
 


So the question is to find out where it disconnects I assume??

Thinking about it, the point where it will leave the circle is going to be the point where the velocity exceeds the velocity needed to keep the object in the at circle (and you have a formula that allows you to calculate that) so why not calculate the velocity needed to keep the object in that circle and find out at what point, using energy, it will equal that value because at the point where it exceeds that value , it will leave the circle. Of course you may need Newton's laws and kinemeatics to get this info.
 


Hi Plutonium,

You made a very nice picture (with the ball changing shape as moving downward, it must have some deeper meaning... )

Draw the forces acting on the ball, and ask yourself the questions:

What force ensures motion along a circle of radius R with velocity v? What is the magnitude and direction of this force? Can the forces exerted on the ball result in the appropriate force that keeps the ball on track?

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
11
Views
2K
  • · Replies 32 ·
2
Replies
32
Views
3K
Replies
43
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K