Ball Speed at Window Top from 38.8m Building: 13m in 2s

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SUMMARY

A ball is thrown downward from a height of 38.8 meters and reaches the top of a window located 13.0 meters above the ground in 2.00 seconds. The speed of the ball as it passes the top of the window is calculated using kinematic equations. The distance between the top of the building and the top of the window is determined to be 25.8 meters. The kinematic equation used for this calculation is v = u + at, where 'u' is the initial velocity, 'a' is the acceleration due to gravity, and 't' is the time.

PREREQUISITES
  • Understanding of kinematic equations
  • Knowledge of gravitational acceleration (9.81 m/s²)
  • Basic algebra for solving equations
  • Familiarity with projectile motion concepts
NEXT STEPS
  • Study the kinematic equation v = u + at in detail
  • Explore examples of projectile motion problems
  • Learn about the effects of air resistance on falling objects
  • Investigate the relationship between initial velocity and time in free fall
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Physics students, educators, and anyone interested in understanding the principles of motion and kinematics in real-world scenarios.

mbecker19
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A ball is thrown downward from the top of a building that is 38.8 m tall. The ball passes the top of a window 13.0 m above the ground 2.00 s after being thrown. What is the speed of the ball as it passes the top of the window?
 
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Find the distance between the top of the building and the top of the window.Then using kinamatic equation find the velocity.
 

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