A Ballentine: Decoherence doesn't resolve the measurement problem

  • #51
martinbn said:
The definition of a phonon says "A phonon is the quantum mechanical description of an elementary vibrational motion in which a lattice of atoms or molecules uniformly oscillates at a single frequency." How is that an object?!
Is there a reasonably rigorous definition of "photon" that does not invite the same question? I'm asking here, not arguing.
 
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  • #52
martinbn said:
The definition of a phonon says "A phonon is the quantum mechanical description of an elementary vibrational motion in which a lattice of atoms or molecules uniformly oscillates at a single frequency." How is that an object?!
You didn't answer my question(s). And by the way, the definition is wrong. A superposition of phonons of different frequencies is a phonon too.
 
  • #53
Nugatory said:
Is there a reasonably rigorous definition of "photon" that does not invite the same question? I'm asking here, not arguing.
It may be that the same applies for the photon. I didn't bring that up, it was Demystifier. I don't know he did bring it up, I thought that Bohmian mechanics cannot deal with photons, after all they are relativistic. But for me there is at least one crucial difference. The photon can exist on its own, it can propagate in vacuum. The phonon on the other hand cannot, if you remove the lattice of atoms/molecules there are no phonons. Also I thought that elementary particles correspond to irreducible representations of so and so group, and there aren't any for phonons.
 
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  • #54
Demystifier said:
You didn't answer my question(s).
Giving the definition does answer your questions. You insists that the phonon is an object, you need to justify it.
Demystifier said:
And by the way, the definition is wrong. A superposition of phonons of different frequencies is a phonon too.
Definitions cannot be wrong. They can be inconstant or useless, but not wrong. In any case in your definition you allow that a superposition of phonons is also a phonon. Doesn't that make it even less of an object?
 
  • #55
martinbn said:
It may be that the same applies for the photon. I didn't bring that up, it was Demystifier. I don't know he did bring it up, I thought that Bohmian mechanics cannot deal with photons, after all they are relativistic. But for me there is at least one crucial difference. The photon can exist on its own, it can propagate in vacuum. The phonon on the other hand cannot, if you remove the lattice of atoms/molecules there are no phonons. Also I thought that elementary particles correspond to irreducible representations of so and so group, and there aren't any for phonons.

Feynman developed a reformulation of electromagnetism that eliminated the electromagnetic field as an independent variable. In his reformulation, the electromagnetic field was completely determined by the motions of charged particles. I don't know whether a Bohmian version of that theory might be possible.
 
  • #56
martinbn said:
In any case in your definition you allow that a superposition of phonons is also a phonon. Doesn't that make it even less of an object?
1) Is wave function an object? Is vector an object?
2) Is photon an object?
3) Is Schrodinger cat an object?
 
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  • #57
Demystifier said:
1) Is wave function an object? Is vector an object?
2) Is photon an object?
3) Is Schrodinger cat an object?

I think that the issue is more well-constrained than that. In Bohmian mechanics (the nonrelativistic version), there is an associated wave function, ##\psi(x_1, y_1, z_1, x_2, y_2, z_2, ..., t)##. The triples ##(x_j, y_j, z_j)## are interpreted to be the location of particle number ##j##. So it seems that you have to figure out what a "particle" is in order to apply Bohmian mechanics. Quantum mechanics in its Dirac formalism seems a little more general, in that you can stipulate arbitrary states of the system; states don't have to be associated with particle positions.
 
  • #58
Demystifier said:
1) Is wave function an object? Is vector an object?
2) Is photon an object?
3) Is Schrodinger cat an object?
1) No, no. These are not physical objects.
2), 3) Yes, yes.

You keep asking questions, but you give no answers nor explanations.
1) What is an object?
2) Why is the phonon an object?
 
  • #59
Demystifier said:
define "object"!

You gave a phonon as an example of an object that doesn't have a definite position in BM. You must have had some definition of "object" in mind in order to make that claim. What definition was it?
 
  • #60
PeterDonis said:
You gave a phonon as an example of an object that doesn't have a definite position in BM. You must have had some definition of "object" in mind in order to make that claim. What definition was it?
For our purposes, an object is anything that, in principle, can cause a click in a detector.
 
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  • #61
martinbn said:
1) No, no. These are not physical objects.
2), 3) Yes, yes.

You keep asking questions, but you give no answers nor explanations.
1) What is an object?
2) Why is the phonon an object?
Before I answer you, please explain me the main difference between photon and phonon that reflects the idea that one is an object and another isn't.
 
  • #62
Demystifier said:
Before I answer you, please explain me the main difference between photon and phonon that reflects the idea that one is an object and another isn't.
I said that in post #53. For me it is important to distinguish objects from collective behavior of objects. A football crowd that is chanting is different from one that isn't, but it is pointless to say that there is an object "chant".
Demystifier said:
For our purposes, an object is anything that, in principle, can cause a click in a detector.
I disagree, I think for the purposes here it is way too vague. Would you say that a gravitational wave is an object, given that the space-time of such a wave is empty?!
 
  • #63
Demystifier said:
For our purposes, an object is anything that, in principle, can cause a click in a detector.
So the Moon is not an object?
 
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  • #64
A. Neumaier said:
Demystifier said:
For our purposes, an object is anything that, in principle, can cause a click in a detector.
So the Moon is not an object?
Heh, I'm pretty sure the Moon would cause a gigantic click when it hits your detector... :biggrin:
 
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  • #65
martinbn said:
I said that in post #53. For me it is important to distinguish objects from collective behavior of objects. A football crowd that is chanting is different from one that isn't, but it is pointless to say that there is an object "chant".
A photon is a collective excitation of quantum electromagnetic field.

martinbn said:
Would you say that a gravitational wave is an object
Yes I would.
 
  • #66
A. Neumaier said:
So the Moon is not an object?
It's not difficult to construct a device that clicks whenever the (picture of the) Moon appears in the telescope.
 
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  • #67
martinbn said:
The photon can exist on its own, it can propagate in vacuum.
And what is the definition of vacuum? You will probably say - the absence of particles. Fine, but then what is the definition of a particle? Do you see a circularity here?

martinbn said:
The phonon on the other hand cannot, if you remove the lattice of atoms/molecules there are no phonons.
Likewise, if you remove the lattice of electromagnetic fields (in lattice regularization of quantum electrodynamics), then there are no photons.
 
  • #68
Ghostly Object or low-lying quanta? Still Object though..:woot:
 
  • #69
Hi,

There are many words such as object, property, phenomenon that are open to interpretation in physics.

"misnaming an object is adding up misery in this world". (Albert Camus)

/Patrick
 
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  • #70
Demystifier said:
For our purposes, an object is anything that, in principle, can cause a click in a detector.
Isn't that a too vague criterion? Then a rain bow and even the blue sky would be an object. I wonder what is not an object but can be seen, felt, tasted etc.
 

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