Barometric formula and height ratios

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Homework Help Overview

The discussion revolves around the barometric formula in the context of an isothermal atmosphere, specifically focusing on deriving the ratio of pressures at two different heights.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the division of the barometric formula at two heights to derive a pressure ratio. Questions arise regarding algebraic manipulation of exponential functions.

Discussion Status

Some participants have provided guidance on manipulating the exponential terms, while others express moments of realization regarding the algebra involved. The conversation reflects a collaborative effort to clarify understanding without reaching a definitive conclusion.

Contextual Notes

One participant mentions feeling uncertain about their algebra skills, indicating a potential barrier to fully engaging with the problem. There is also a note on the use of notation, suggesting a focus on clarity in mathematical expressions.

shyguy79
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Homework Statement


Starting from the barometric formula for a thin, isothermal atmosphere, show that the ratio of the pressure P(z2) at height z2 to the pressure P(z1) at height z1 is given by

P(z2)/P(z1) = e(-(z2-z1)/y) where y is the scale height

Homework Equations


Barometric formula: P(z) =P(0) e(-z/y)

The Attempt at a Solution


looks easy but i just can see how?
 
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If it looks easy, then you should be able to see how.
Have you tried writing P(z1) and P(z2) in the barometric formula and just dividing them?

aside: on notation:

P(z)=P(0).exp(-z/y) ... in plain text, or, in LaTeX (worth learning)
[tex]P(z)=P_0 e^{-z/y}[/tex]
 
Last edited:
I'm afraid my algebra is a little rusty, how do you divide e(-z2/y) by e(-z1/y)?
 
property of powers
[tex]x^a x^b = x^{a+b}[/tex]... it's the same for the exponential function.
 
got it... just clicked
 
:) I get blind spots like that sometimes.
 
Yeah, thanks for the memory jog :-)
 

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