Baseball Kinematics: Calculating Acceleration from Stopping Distance

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SUMMARY

The discussion focuses on calculating the acceleration of a baseball that comes to a stop after hitting a catcher's mitt. The initial velocity (Vi) is 30 m/s, and the stopping distance (d) is 5.0 cm (0.05 m). Using the kinematic equation Vf^2 = Vi^2 + 2a.d, the calculated acceleration (a) is -600 m/s². The method is confirmed as correct, but participants emphasize the importance of careful calculations to avoid errors.

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Homework Statement



A baseball traveling at 30 m/s [f] hits a catcher's mitt and comes to a stop in a distance of 5.0 cm. What is the acceleration?

Homework Equations


The Attempt at a Solution


Vi = 30 m/s
d = 0.05 m
a = ?
Vf = 0

Vf^2 = Vi^2 + 2a.d
0 = 90 m^2/s^2 + 2a.0.05m
- 90 m^2/s^2 = 2a.0.05m
-30 m^2/s^2 = a.0.05m
a = -600 m/s^2
 
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novawinters said:
- 90 m^2/s^2 = 2a.0.05m
-30 m^2/s^2 = a.0.05m

90 divided by 2 is 45 :-p

ehild
 
The method is correct but be careful with calculations.
 

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