The equation starts with dy/dt = ay - b, and initial condition y(0) = y_o and y_o is an arbitrary value. The book says this can be rewritten as:(adsbygoogle = window.adsbygoogle || []).push({});

(dy/dt)/[y - (b/a)] = a. But I don't see how do make that step algebraically. How can the original be rewritten like that?

A problem at the end of the chapter appears to be designed to use the above equation.

(dy/dt) = -y + 5

Am I correct in assuming I should rewrite it as this?

(dy/dt)/[y - 5/(-1)] = -1

Then follow the steps to solve that? Beginning with:

(ln[y - (5/(-1)]) = -1t + C

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# Homework Help: Basic Differential Eqn - initial value problem

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