A closed vessel contains liquid water at equilibrium with its vapor at 100C and 1 atm. 1 gram of water vapor occupies 1670cm^3. Hvap = 2250Jg^-1. How many molecules are there per cm^3 of vapor?How many vapor molecules strike each cm^2 of liquid surface per second?
PV = NKT
Q = lm
The Attempt at a Solution
N = PV/KT = 3.3E26 molecules of vapor
I used P = 1.013 E5 N m^-2
V = 16.7m^3
T = 373
Not sure how to get how much water there is.
Answers are: 2E19 molecules cm^-2 ; 3.3E23 impacts per second