- #1
tamtam402
- 201
- 0
Hey guys, I have a butterworth high-pass filter, and I was asked to find it's temporal response equation to the u(t) function. That part was easy, using basic Laplace tables I was able to find the following equation:
y(t)=√2 e^(-31100t) *cos(31000t+π/4)u(t)
However, I'm supposed to be able to use that result to find the output equation (in the time domain) for a constant signal of magnitude 1V from 0 to 0.5ms, and 0V from 0.5 to 1ms. I'm at a loss here, because when using simulink (in Matlab) to simulate the response, I see that the output "responds" to the 1V to 0V transition. That means I can't simply use my equation with u(t) = 1 for t = 0 to 0.5ms, and u(t) = 0 for t = 0.5 to 1ms. What am I supposed to do?
y(t)=√2 e^(-31100t) *cos(31000t+π/4)u(t)
However, I'm supposed to be able to use that result to find the output equation (in the time domain) for a constant signal of magnitude 1V from 0 to 0.5ms, and 0V from 0.5 to 1ms. I'm at a loss here, because when using simulink (in Matlab) to simulate the response, I see that the output "responds" to the 1V to 0V transition. That means I can't simply use my equation with u(t) = 1 for t = 0 to 0.5ms, and u(t) = 0 for t = 0.5 to 1ms. What am I supposed to do?