Basic Question Regarding the Combined Gas Law/Equation

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Discussion Overview

The discussion revolves around the requirements for temperature units in the combined gas law equation, specifically whether temperatures T1 and T2 must be expressed in Kelvin or if other units can be used as long as consistency is maintained.

Discussion Character

  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant questions if T1 and T2 in the combined gas law must be in Kelvin or if other temperature units can be used with consistent unit application.
  • Another participant suggests that temperatures could be in degrees Fahrenheit, provided an adjustment is made to define absolute zero in that scale.
  • A different participant notes that Kelvin is the Celsius scale with an absolute zero origin, while Rankine serves a similar purpose for Fahrenheit.
  • It is proposed that Celsius could be used, but adjustments must be made to account for the difference from Kelvin, specifically mentioning a conversion factor of -273.15.

Areas of Agreement / Disagreement

Participants express differing views on the acceptable temperature units for the combined gas law, with no consensus reached on whether only Kelvin is valid or if other units can be appropriately adjusted.

Contextual Notes

There are unresolved considerations regarding the necessary adjustments for temperature scales and the implications of using non-Kelvin units in the equation.

Denyven
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Hello All,
I was wondering, in the combined gass law \frac{p_{1}V_{1}}{T_{1}}=\frac{p_{2}V_{2}}{T_{2}} Does T_{1} and T_{2} have to be in kelvins, or can they be any other unit of temperature as long as a consistency of units is used?

Thanks
 
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Hello Denyven! :smile:

They could be in degrees Fahrenheit, provided it was adjusted to º F0, say, where absolute zero is at 0º Fo. :wink:

Without that adjustment, the equation just won't work. :redface:
 
Just to let you know, as Kelvin is the Celsius scale with the origin at zero, so Rankine is the Fahrenheit scale with the origin at zero.

However, the scale must be set up so that the absolute coldest temperature is zero.
 
You could represent it in, say, celsius. Then you would have \frac{pV}{T(K)}=\frac{pV}{T(^\circ C)-273.15}. You could do it similarily with Fahrenheit if you want, but for simple equations, use the kelvin scale.
 

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