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A Be atom is traveling with 60 kev kinetic energy and splits into two helium atoms, and the process itself releases 92.2 kev. One helium atom moves at a 30 degree angle with respect to x. find the direction of motion of the second helium atom and find the velocity of each helium atom.

My problem: to get the y component info, i feel like i have to assume the other helium atom is traveling at -30 degree angle and that both he atoms have the same velocity. is this wrong? if so, how would i go about solving this?

So far i have 7.338 x 10^12 = V1^2 + V2^2 and sin(30)V1 = -sin(theta)v2

Thank yoU!