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Homework Help: Beam hinged to wall with a cable (torque, etc)

  1. Nov 5, 2006 #1
    Hi. I've tried to answer this questions four times and so far none of my answers have been correct. Any help is greatly appreciated!

    A uniform 48 kg (m) beam at an angle of 24 degrees (theta) with respect to the horizontal has length of 38 m (L). It is supported by a pin and horizontal cable. The acceleration of gravity is 9.8 m/s^2 (g). What is the magnitude of the total force exerted by the pin on the beam?

    So far:

    [tex]\sum F_x = F_h - T = 0[/tex] horizontal component of pin - tension of cable
    [tex]\sum F_y = F_v - mg = 0[/tex] vertical component of pin - mass of beam * gravity
    [tex]\sum \tau = \sin \theta L T - \cos \theta L m g = 0[/tex]

    Does this look ok to you? For the torque, I'm trying to use the moment arm times the magnitude of the force.

    Thank you.
  2. jcsd
  3. Nov 5, 2006 #2
    The last equation should have been:
    [tex]\sum \tau = \sin \theta L T - \cos \theta \frac{L}{2} m g = 0[/tex]
    and that took care of it.
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