Hi. I've tried to answer this questions four times and so far none of my answers have been correct. Any help is greatly appreciated!(adsbygoogle = window.adsbygoogle || []).push({});

A uniform 48 kg (m) beam at an angle of 24 degrees (theta) with respect to the horizontal has length of 38 m (L). It is supported by a pin and horizontal cable. The acceleration of gravity is 9.8 m/s^2 (g). What is the magnitude of the total force exerted by the pin on the beam?

So far:

[tex]\sum F_x = F_h - T = 0[/tex] horizontal component of pin - tension of cable

[tex]\sum F_y = F_v - mg = 0[/tex] vertical component of pin - mass of beam * gravity

[tex]\sum \tau = \sin \theta L T - \cos \theta L m g = 0[/tex]

Does this look ok to you? For the torque, I'm trying to use the moment arm times the magnitude of the force.

Thank you.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Beam hinged to wall with a cable (torque, etc)

**Physics Forums | Science Articles, Homework Help, Discussion**