Beginning physics, in finding the electric field for a uniform line charg

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SUMMARY

The discussion focuses on calculating the electric field generated by a uniform line charge with a linear charge density of λ = 4.4 nC/m along the x-axis. The total charge of the line charge is determined to be 22 nC using the formula Q = λ * length. For calculating the electric field at various points, the equation E = kQ/[x^2] is incorrectly applied, as it is only valid for point charges. Instead, the problem requires the use of calculus to account for the contributions of infinitesimal charge segments along the line charge.

PREREQUISITES
  • Understanding of linear charge density and its calculation
  • Familiarity with Coulomb's law and electric field equations
  • Basic knowledge of calculus for integrating charge distributions
  • Concept of point charges versus extended charge distributions
NEXT STEPS
  • Study the derivation of electric fields from continuous charge distributions
  • Learn about the method of integration in electrostatics
  • Explore the application of the superposition principle in electric fields
  • Investigate the differences between point charges and extended charge distributions in electric field calculations
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Students and educators in physics, particularly those focusing on electromagnetism, as well as anyone involved in solving problems related to electric fields and charge distributions.

krtica
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Q:
A uniform line charge that has a linear charge density λ = 4.4 nC/m is on the x-axis between x = 0 to x = 5.0 m.
(a) What is its total charge?

(b) Find the electric field on the x-axis at x = 6 m.

(c) Find the electric field on the x-axis at x = 11.0 m.

(d) Find the electric field on the x-axis at x = 240 m.


To solve for a, I used the equation Q=lambda*length. My answer is 22nC, which is correct.

To solve for the remaining portion of the question, I used E=kQ/[x^2], where I took x to be (L+a-x). L is defined as the length of the rod (5m), a is the difference between the given position and the rod (for b, 1m), and x is the distance from the origin to the midpoint of the rod (2.5m).
 
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krtica said:
To solve for the remaining portion of the question, I used E=kQ/[x^2], where I took x to be (L+a-x). L is defined as the length of the rod (5m), a is the difference between the given position and the rod (for b, 1m), and x is the distance from the origin to the midpoint of the rod (2.5m).

The fact that you didn't get the right answer proves that E=kQ/[x^2] can only be used for point masses, not for extended objects. (The sphere is an exception, but that's a special case.) To solve this problem, you have to use calculus. What's the charge contributed by a length "dx" of rod a distance "x" from the given position?
 

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